Translation for 'finite' from English to Russian
 ADJ finite | more finite | most finite
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## Translation for 'finite' from English to Russian

finite
Usage Examples English
• Another important verbal distinction in Abkhaz is finite versus non-finite, referring to the duration of the action.
• Subgroups of residually finite groups are residually finite, and direct products of residually finite groups are residually finite.
• Every σ-finite measure is s-finite, the converse is not true. For a proof and counterexample see s-finite measure#Relation to σ-finite measures.
• Grids of this type appear on graph paper and may be used in finite element analysis, finite volume methods, finite difference methods, and in general for discretization of parameter spaces.
• A second major distinction concerns the difference between finite and non-finite clauses.

• Finite morphisms are quasi-finite. A quasi-finite proper morphism locally of finite presentation is finite. Indeed, a morphism is finite if and only if it is proper and locally quasi-finite.
• The elements of any finite subset can be ordered into a finite sequence. There are only countably many finite sequences, so also there are only countably many finite subsets.
• The Krohn–Rhodes theorem for finite semigroups states that every finite semigroup "S" is a divisor of a finite alternating wreath product of finite simple groups, each a divisor of "S", and finite aperiodic semigroups (which contain no nontrivial subgroups).
• In mathematics, the finite lattice representation problem, or finite congruence lattice problem, asks whether every finite lattice is isomorphic to the congruence lattice of some finite algebra.
• Finite morphisms are quasi-finite, but not all morphisms having finite fibers are quasi-finite, and morphisms of finite type are usually not quasi-finite.

• A poset is called locally finite if every bounded interval is finite.
• The simplest definition of an infinite matroid is to require "finite rank"; that is, the rank of "E" is finite.
• A class with finite thickness certainly satisfies MEF-condition and MFF-condition; in other words, finite thickness implies M-finite thickness.
• If the machine [...] does not halt in finite steps, then [...] is false in any finite model, since there's no finite computation record of [...] that ends with halting.
• By definition, a finite [...] -algebra is of finite type, but the converse is false: the polynomial ring [...] is of finite type but not finite.